How do I make it print the outputs on same line?-CodePudding

I am trying to open two files and collect information for the years 2010 to 2019 and report the mean and standard deviation of just the claims in that year

mean_file = open('data/mean.txt', 'r')
std_file = open('data/std.txt', 'r')
count = 2009

for line in std_file:
    std = float(line)
    for line in mean_file:
        mean = float(line)
    count  = 1
    print('Year',count, 'Mean:', mean, 'Standard Deviation:', std)

mean_file.close()
std_file.close()

I have the code above. The output I got is

Year 2019 Mean: 217557.4 Standard Deviation: 82296.33
Year 2019 Mean: 217557.4 Standard Deviation: 77808.0
Year 2019 Mean: 217557.4 Standard Deviation: 66939.77
Year 2019 Mean: 217557.4 Standard Deviation: 65486.56
Year 2019 Mean: 217557.4 Standard Deviation: 59126.12
Year 2019 Mean: 217557.4 Standard Deviation: 58712.14
Year 2019 Mean: 217557.4 Standard Deviation: 55465.54
Year 2019 Mean: 217557.4 Standard Deviation: 44621.54
Year 2019 Mean: 217557.4 Standard Deviation: 47821.1
Year 2019 Mean: 217557.4 Standard Deviation: 43170.7

Each time I change the position of the indent, it gives a different answer. I want the mean and standard deviation to be printed on the same line simultaneously just like the output below. I want the output to be like below. How do I make it print exactly like the output below?

Year 2010 Mean: 455692.98 Standard Deviation: 82296.33
Year 2011 Mean: 409110.4 Standard Deviation: 77808.0
Year 2012 Mean: 372226.67 Standard Deviation: 66939.77
Year 2013 Mean: 341826.79 Standard Deviation: 65486.56
Year 2014 Mean: 306567.67 Standard Deviation: 59126.12
Year 2015 Mean: 276956.5 Standard Deviation: 58712.14
Year 2016 Mean: 263900.21 Standard Deviation: 55465.54
Year 2017 Mean: 243116.25 Standard Deviation: 44621.54
Year 2018 Mean: 220894.98 Standard Deviation: 47821.1
Year 2019 Mean: 217557.4 Standard Deviation: 43170.7

CodePudding user response：

EDIT: Apologies, made a mistake. I see where you are coming from. All the points below, other than indentation, still apply. To fix this error, you should use zip, which allows you to iterate both files at once:

with open('std.txt', 'r') as std_file:
    with open('means.txt', 'r') as mean_file:
        for line in zip(std_file,mean_file):
            std = float(line[0])
            mean = float(line[1])
            count  = 1
            print('Year',count, 'Mean:', mean, 'Standard Deviation:', std)

Which gives us:

Year 2010 Mean: 455692.98 Standard Deviation: 82296.33
Year 2011 Mean: 409110.4 Standard Deviation: 77808.0
Year 2012 Mean: 372226.67 Standard Deviation: 66939.77
Year 2013 Mean: 341826.79 Standard Deviation: 65486.56
Year 2014 Mean: 306567.67 Standard Deviation: 59126.12
Year 2015 Mean: 276956.5 Standard Deviation: 58712.14
Year 2016 Mean: 263900.21 Standard Deviation: 55465.54
Year 2017 Mean: 243116.25 Standard Deviation: 44621.54
Year 2018 Mean: 220894.98 Standard Deviation: 47821.1
Year 2019 Mean: 217557.4 Standard Deviation: 43170.7

Some quick pointers that will make your code easier to read, and thus easier to debug: Use context managers (i.e. with statements), and don't reuse iteration variables in nested for-loops.

Using a context manager automatically opens and closes a file, and is generally safer. You can do it like so:

with open('data/std.txt', 'r') as std_file:
    with open('data/mean.txt', 'r') as mean_file:
        #do stuff

Additionally, reusing line in both for-loops is not only bad practice, but will inevitably cause the program to rewrite variables you still want. ~~Finally, your indentation is wrong: you are only printing after iteration through ALL of the mean file, and as such will always get the same output for mean.~~ Putting this all together, we have.

count = 2009
with open('data/std.txt', 'r') as std_file:
    with open('data/mean.txt', 'r') as mean_file:
        for line_std in std_file:
            std = float(line_std)
            for line_mean in mean_file:
                mean = float(line_mean)
                count  = 1
                print('Year',count, 'Mean:', mean, 'Standard Deviation:', std)

~~Which should work as intended.~~ SEE ABOVE FOR FIXED CODE

CodePudding user response：

for sline, mline in zip(std_file, mean_file):
   std = float(line)
   mean = float(line)
   count = count 1
   print('Year',count, 'Mean:', mean, 'Std:', std)