Continue in if conditional python loop is not working-CodePudding

a = ['AKDYYDSSGYHFDY', 'AKDDSSGYYFYFDY', 'AKDAGDYYYYGMDV']

match = ['DS', 'DV', 'DY']

counter = 0
for i in a:
    for j in match:
        if j in i:
            print(i, j)
            counter = counter 1
            continue

print(counter)

Results are

AKDYYDSSGYHFDY DS
AKDYYDSSGYHFDY DY
AKDDSSGYYFYFDY DS
AKDDSSGYYFYFDY DY
AKDAGDYYYYGMDV DV
AKDAGDYYYYGMDV DY

6

I was expecting that it would identify the first pattern DS in the first string in list a, then move to next element. However, it proceed to identify DY as well. What am I doing incorrectly? Any help is appreciated.

Thanks

CodePudding user response：

Try to replace continue with break like this

a = ['AKDYYDSSGYHFDY', 'AKDDSSGYYFYFDY', 'AKDAGDYYYYGMDV']

match = ['DS', 'DV', 'DY']

counter = 0
for i in a:
    for j in match:
        if j in i:
            print(i, j)
            counter = counter 1
            break

print(counter)

Output:

AKDYYDSSGYHFDY DS
AKDDSSGYYFYFDY DS
AKDAGDYYYYGMDV DV
3

сontinue actually means that you go to the next iteration of for loop. Since you have continue inside j loop it doesn't influence on i loop and simply iterates more on j.

break instead stops iterations on j loop and let's i loop to proceed on the next iteration