If I have a class for BST, would I do something like array = new BST[size]
in order to create an array of BST's?
Additionally, if I did end up creating an array, what would each element in the array be when it's first created?
CodePudding user response:
Yes that would create an array, but as already said you should prefer
vector<BST> array(size);
Either way the BSTs would be default initialised. So whatever your BST default constructor does, that's what the BSTs will be.
CodePudding user response:
Following code snippet may help you to understand BST Class in C :
// C program to demonstrate insertion
// in a BST recursively.
#include <iostream>
using namespace std;
class BST {
int data;
BST *left, *right;
public:
// Default constructor.
BST();
// Parameterized constructor.
BST(int);
// Insert function.
BST* Insert(BST*, int);
// Inorder traversal.
void Inorder(BST*);
};
// Default Constructor definition.
BST ::BST()
: data(0)
, left(NULL)
, right(NULL)
{
}
// Parameterized Constructor definition.
BST ::BST(int value)
{
data = value;
left = right = NULL;
}
// Insert function definition.
BST* BST ::Insert(BST* root, int value)
{
if (!root) {
// Insert the first node, if root is NULL.
return new BST(value);
}
// Insert data.
if (value > root->data) {
// Insert right node data, if the 'value'
// to be inserted is greater than 'root' node data.
// Process right nodes.
root->right = Insert(root->right, value);
}
else {
// Insert left node data, if the 'value'
// to be inserted is smaller than 'root' node data.
// Process left nodes.
root->left = Insert(root->left, value);
}
// Return 'root' node, after insertion.
return root;
}
// Inorder traversal function.
// This gives data in sorted order.
void BST ::Inorder(BST* root)
{
if (!root) {
return;
}
Inorder(root->left);
cout << root->data << endl;
Inorder(root->right);
}
// Driver code
int main()
{
BST b, *root = NULL;
root = b.Insert(root, 50);
b.Insert(root, 30);
b.Insert(root, 20);
b.Insert(root, 40);
b.Insert(root, 70);
b.Insert(root, 60);
b.Insert(root, 80);
b.Inorder(root);
return 0;
}