F-string returns file object name-CodePudding

Trying to understand the output of the following code:


  1 #!/usr/bin/python3
  2
  3 from os.path import exists
  4
  5 filename = input("What file do you want to erase?: ")
  6
  7 check = exists(filename)
  8
  9 if check == True:
 10     target = open(filename, "r ")
 11     print(f'Your {target} file is now open for editing ')
 12     input("RETURN to ERASE.  CTRL   C to abort. " )
 13     target.truncate()
 14     print (f"Your {filename} file is now empty. ")
 15     target.write("#!/usr/bin/python3 ")
 16     target.close()
 17 elif check == False:
 18     print(f'That file  does not exist.  Come back later and try again ')
 19
 20
 21 another_file = input("Give me another file to erase:  ")
 22
 23 target = open(another_file, "r ")
 24
 25 print(f"This is the name {another_file} of the file you opened. ")
 26

OUTPUT

The code on line 11 outputs the following:

Your <_io.TextIOWrapper name='file1.txt' mode='r ' encoding='UTF-8'> file is now open for editing

All other f-string instances output the actual filename.

"Your file1.txt file is now empty....etc"

Trying to understand why that is. If anyone has any insights, I'd greatly appreciate it.

Thx!

CodePudding user response：

Because you use "targer", "target" is file object. Use "filename"

print(f'Your {filename} file is now open for editing ')