How do I pop a stack till it's empty using a FOR loop?-CodePudding

S=['TOM', 'HARRY', 'MAMA', 'JOE']
print(S)
for x in S:
    print(S.pop())
    if S==[]:
        print("Empty")
        break

Using a for loop should iterate through the entire list and give me all the items followed by 'Empty' but instead, it only gives two elements

What I'm getting-

['TOM', 'HARRY', 'MAMA', 'JOE']
JOE
MAMA

What I was expecting-

['TOM', 'HARRY', 'MAMA', 'JOE']
JOE
MAMA
HARRY
TOM
Empty

This is my first question here so any tips on how to frame questions would be appreciated.

CodePudding user response：

The main issue with your code is that you can't loop over a list while doing changes to that list. If you want to use a for loop (timgeb suggestion is great btw). You could do this:

for _ in range(len(S)):
    print(S.pop())

This will take care of popping all the items of the list

CodePudding user response：

You see an unexpected result because you're mutating the list while iterating over it. Note that you're not doing anything with x, so a for loop is not the right tool here.

Use a while loop.

while S:
    print(S.pop())

print('empty')

CodePudding user response：

S=['TOM', 'HARRY', 'MAMA', 'JOE']
print(S)
for x in S[::-1]:
    print(S.pop())
    if S==[]:
        print("Empty")
        break