Split Pandas Series Tuple on the fly to Pandas Column-CodePudding

I want to split the Pandas Series tuple on the fly in to multiple columns. Generate dummy data using code below:

df = pd.DataFrame(data={'a':[1, 2, 3, 4, 5, 6]})
df['b'] = pd.Series([(np.nan, 1), ('AB', 10), ('CD', 1), (3, 1), (4, 1), ('NA', 1)]).str[0]
df['c'] = pd.Series([(np.nan, 1), ('AB', 10), ('CD', 1), (3, 1), (4, 1), ('NA', 1)]).str[1]

How can I create column b and c in 1 line of code?

I've tried below code but it doesn't split as per the requirement.

df[['b', 'c']] = pd.Series([(np.nan, 1), ('AB', 10), ('CD', 1), (3, 1), (4, 1), ('NA', 1)]).str[0:2]

CodePudding user response：

Assign both str to 2 columns:

df = pd.DataFrame(data={'a':[1, 2, 3, 4, 5, 6]})

s = pd.Series([(np.nan, 1), ('AB', 10), ('CD', 1), (3, 1), (4, 1), ('NA', 1)])

df['b'], df['c'] = s.str[0], s.str[1]

Or create 2 columns DataFrame:

s = pd.Series([(np.nan, 1), ('AB', 10), ('CD', 1), (3, 1), (4, 1), ('NA', 1)])

df[['b', 'c']] = pd.DataFrame(s.tolist(), index=df.index)
print(df)
   a    b   c
0  1  NaN   1
1  2   AB  10
2  3   CD   1
3  4    3   1
4  5    4   1
5  6   NA   1

What is same like one lines code:

df['b'], df['c'] = pd.Series([(np.nan, 1), ('AB', 10), ('CD', 1), (3, 1), (4, 1), ('NA', 1)]).str[0], pd.Series([(np.nan, 1), ('AB', 10), ('CD', 1), (3, 1), (4, 1), ('NA', 1)]).str[1]
df[['b', 'c']] = pd.DataFrame(pd.Series([(np.nan, 1), ('AB', 10), ('CD', 1), (3, 1), (4, 1), ('NA', 1)]).tolist(), index=df.index)