I have a df that looks like this (shortened):
DateTime Value Date Time
0 2022-09-18 06:00:00 5.4 18/09/2022 06:00
1 2022-09-18 07:00:00 6.0 18/09/2022 07:00
2 2022-09-18 08:00:00 6.5 18/09/2022 08:00
3 2022-09-18 09:00:00 6.7 18/09/2022 09:00
8 2022-09-18 14:00:00 7.9 18/09/2022 14:00
9 2022-09-18 15:00:00 7.8 18/09/2022 15:00
10 2022-09-18 16:00:00 7.6 18/09/2022 16:00
11 2022-09-18 17:00:00 6.8 18/09/2022 17:00
12 2022-09-18 18:00:00 6.4 18/09/2022 18:00
13 2022-09-18 19:00:00 5.7 18/09/2022 19:00
14 2022-09-18 20:00:00 4.8 18/09/2022 20:00
15 2022-09-18 21:00:00 5.4 18/09/2022 21:00
16 2022-09-18 22:00:00 4.7 18/09/2022 22:00
17 2022-09-18 23:00:00 4.3 18/09/2022 23:00
18 2022-09-19 00:00:00 4.1 19/09/2022 00:00
19 2022-09-19 01:00:00 4.4 19/09/2022 01:00
22 2022-09-19 04:00:00 3.5 19/09/2022 04:00
23 2022-09-19 05:00:00 2.8 19/09/2022 05:00
24 2022-09-19 06:00:00 3.8 19/09/2022 06:00
I want to create a new column where i split the between day and night like this:
00:00 - 05:00 night , 06:00 - 18:00 day , 19:00 - 23:00 night
But apparently one can't use same label? How can I solve this problem? Here is my code
df['period'] = pd.cut(pd.to_datetime(df.DateTime).dt.hour,
bins=[0, 5, 17, 23],
labels=['night', 'morning', 'night'],
include_lowest=True)
It's returning
ValueError: labels must be unique if ordered=True; pass ordered=False for duplicate labels
CodePudding user response：
if i understood correctly, if time is between 00:00 - 05:00 or 19:00 - 23:00, you want your new column to say 'night', else 'day', well here's that code:
df['day/night'] = df['Time'].apply(lambda x: 'night' if '00:00' <= x <= '05:00' or '19:00' <= x <= '23:00' else 'day')
or you can add ordered = false parameter using your method
input ->
df = pd.DataFrame(columns=['DateTime', 'Value', 'Date', 'Time'], data=[
['2022-09-18 06:00:00', 5.4, '18/09/2022', '06:00'],
['2022-09-18 07:00:00', 6.0, '18/09/2022', '07:00'],
['2022-09-18 08:00:00', 6.5, '18/09/2022', '08:00'],
['2022-09-18 09:00:00', 6.7, '18/09/2022', '09:00'],
['2022-09-18 14:00:00', 7.9, '18/09/2022', '14:00'],
['2022-09-18 15:00:00', 7.8, '18/09/2022', '15:00'],
['2022-09-18 16:00:00', 7.6, '18/09/2022', '16:00'],
['2022-09-18 17:00:00', 6.8, '18/09/2022', '17:00'],
['2022-09-18 18:00:00', 6.4, '18/09/2022', '18:00'],
['2022-09-18 19:00:00', 5.7, '18/09/2022', '19:00'],
['2022-09-18 20:00:00', 4.8, '18/09/2022', '20:00'],
['2022-09-18 21:00:00', 5.4, '18/09/2022', '21:00'],
['2022-09-18 22:00:00', 4.7, '18/09/2022', '22:00'],
['2022-09-18 23:00:00', 4.3, '18/09/2022', '23:00'],
['2022-09-19 00:00:00', 4.1, '19/09/2022', '00:00'],
['2022-09-19 01:00:00', 4.4, '19/09/2022', '01:00'],
['2022-09-19 04:00:00', 3.5, '19/09/2022', '04:00'],
['2022-09-19 05:00:00', 2.8, '19/09/2022', '05:00'],
['2022-09-19 06:00:00', 3.8, '19/09/2022', '06:00']])
output ->
DateTime Value Date Time is_0600_0900
0 2022-09-18 06:00:00 5.4 18/09/2022 06:00 day
1 2022-09-18 07:00:00 6.0 18/09/2022 07:00 day
2 2022-09-18 08:00:00 6.5 18/09/2022 08:00 day
3 2022-09-18 09:00:00 6.7 18/09/2022 09:00 day
4 2022-09-18 14:00:00 7.9 18/09/2022 14:00 day
5 2022-09-18 15:00:00 7.8 18/09/2022 15:00 day
6 2022-09-18 16:00:00 7.6 18/09/2022 16:00 day
7 2022-09-18 17:00:00 6.8 18/09/2022 17:00 day
8 2022-09-18 18:00:00 6.4 18/09/2022 18:00 day
9 2022-09-18 19:00:00 5.7 18/09/2022 19:00 night
10 2022-09-18 20:00:00 4.8 18/09/2022 20:00 night
11 2022-09-18 21:00:00 5.4 18/09/2022 21:00 night
12 2022-09-18 22:00:00 4.7 18/09/2022 22:00 night
13 2022-09-18 23:00:00 4.3 18/09/2022 23:00 night
14 2022-09-19 00:00:00 4.1 19/09/2022 00:00 night
15 2022-09-19 01:00:00 4.4 19/09/2022 01:00 night
16 2022-09-19 04:00:00 3.5 19/09/2022 04:00 night
17 2022-09-19 05:00:00 2.8 19/09/2022 05:00 night
18 2022-09-19 06:00:00 3.8 19/09/2022 06:00 day
CodePudding user response：
You have two options.
Either you don't care about the order and you can set ordered=False as parameter of cut:
df['period'] = pd.cut(pd.to_datetime(df.DateTime).dt.hour,
bins=[0, 5, 17, 23],
labels=['night', 'morning', 'night'],
ordered=False,
include_lowest=True)
Or you care to have night and morning ordered, in which case you can further convert to ordered Categorical:
df['period'] = pd.Categorical(df['period'], categories=['night', 'morning'], ordered=True)
output:
DateTime Value Date Time period
0 2022-09-18 06:00:00 5.4 18/09/2022 06:00 morning
1 2022-09-18 07:00:00 6.0 18/09/2022 07:00 morning
2 2022-09-18 08:00:00 6.5 18/09/2022 08:00 morning
3 2022-09-18 09:00:00 6.7 18/09/2022 09:00 morning
8 2022-09-18 14:00:00 7.9 18/09/2022 14:00 morning
9 2022-09-18 15:00:00 7.8 18/09/2022 15:00 morning
10 2022-09-18 16:00:00 7.6 18/09/2022 16:00 morning
11 2022-09-18 17:00:00 6.8 18/09/2022 17:00 morning
12 2022-09-18 18:00:00 6.4 18/09/2022 18:00 night
13 2022-09-18 19:00:00 5.7 18/09/2022 19:00 night
14 2022-09-18 20:00:00 4.8 18/09/2022 20:00 night
15 2022-09-18 21:00:00 5.4 18/09/2022 21:00 night
16 2022-09-18 22:00:00 4.7 18/09/2022 22:00 night
17 2022-09-18 23:00:00 4.3 18/09/2022 23:00 night
18 2022-09-19 00:00:00 4.1 19/09/2022 00:00 night
19 2022-09-19 01:00:00 4.4 19/09/2022 01:00 night
22 2022-09-19 04:00:00 3.5 19/09/2022 04:00 night
23 2022-09-19 05:00:00 2.8 19/09/2022 05:00 night
24 2022-09-19 06:00:00 3.8 19/09/2022 06:00 morning
column:
df['period']
0 morning
1 morning
2 morning
...
23 night
24 morning
Name: period, dtype: category
Categories (2, object): ['morning', 'night']