how can I call the variable b outside the function?-CodePudding

a=1

def choice():
    if a==1 :
        return 'more work to do '
        b='cool'
    else :
        return 'more work to do '
        b='not cool'

print (b)

all I want is to call it outside the function in another much longer code . this is the simple version. thanks a lot.

CodePudding user response：

You could make b a global variable and use the global keyword to modify it within choice. But please don't.

>>> a = 1
>>> b = None
>>> def choice():
...   global b
...   if a == 1: b = "cool"
...   else: b = "not cool"
...
>>> choice()
>>> b
'cool'
>>>

CodePudding user response：

As you've seen, b is a local variable inside choice and can't be referenced outside it. One option is to return the value from choice:

def choice():
    if a == 1:
        return 'cool'
    else:
        return 'not cool'

b = choice()
print(b)

CodePudding user response：

There are 2 ways of achieving this. First of all you can just simply return b along with 'more work to do' like this:

a=1

def choice():
    if a==1 :
        b = 'cool'
        return 'more work to do', b
    else :
        b = 'not cool'
        return 'more work to do', b

moreWorkToDo, b = choice()
print (b)

Another way is to set b as a global variable however it is usually not advised. Global variables can be accessed and modified from anywhere in the code, which can make it difficult to trace the source of a bug. Anyways here is the code:

a=1

def choice():
    global b
    if a==1 :
        b = 'cool'
        return 'more work to do'
    else :
        b = 'not cool'
        return 'more work to do'

moreWorkToDo = choice()
print (b)

CodePudding user response：

You can make b as a global variable to get it done for more info visit below thread Correct Use Of Global Variables In Python 3

a=1
def choice():
     if a==1:
        global b 
        b='cool'
        return 'more work to do '
     else :
        b='not cool'  
        return 'more work to do '
        
print(choice())
print(b)