The open CV cap. Get (7) for return to a negative total video frames-CodePudding

 import cv2 
The import argparse 
The import OS 


Def the parse () : 
Parser=argparse. ArgumentParser (description="This is a example program") 
Parser. Add_argument (
'- video_path' 
Type=STR, 
The default="D:/image/14. Mp4, 
Help="video path.") 
Parser. Add_argument (
'- pic_path' type=STR, default="D:/PIC/13, help=" PIC path. ") 
Args=parser. Parse_args () 
Return the args 

Def get_video_pic (name) : 
Cap=cv2. VideoCapture (name) 
Print (cap) get (7)) 
Print (count) 
For I in range (0, int (count) : 
Cap. The set (1, int (I)) 
# print (cap. The read ()) 
Rval, frame=cap. The read () 
If rval: 
If (I % 5==0) : 
If not OS. Path. The exists (args. Pic_path) : 
OS. Makedirs (args. Pic_path) 
Cv2. Imwrite (args. Pic_path + "/result" + STR (I//5) + 'JPG', frame) # image path 
Cap. Release () 


If __name__=="__main__ ': 
Args=the parse () 
Get_video_pic (args. Video_path)

Print the results as follows: 192153584101141.0, what reason is this excuse me, how to solve, to get the correct number of video frames

CodePudding user response:

Have you solved?