PYTHON-CodePudding

Three side input triangle, determine whether to form a triangle, and output to judge the results, such as: a right triangle, equilateral triangle, isosceles triangle, triangle commonly,

CodePudding user response:

Algorithm or code? Should go to q&a python code channel Posting, ensure to offer

Algorithm about

Input a, b, c,
Increasing sequence sorting, get l [3]

If l [0] + [1] l & gt; L [2], in order to do the following judgment
The triangle mark='general triangle'
If l [0] [0] + [1] l * l * l [1] [2]=l * l [2], print 'right triangle, the triangle mark='
If l [0]=l [1] [2]=l, print 'an equilateral triangle, triangle mark='
If l [0]=l [1] OR [2] OR [0]=l l l [1] [2]=l, print 'isosceles triangle, triangle mark='
Print the triangle mark
Otherwise print 'is not a triangle'

CodePudding user response:

reference 1/f, old coconut response:

algorithm or code? Should go to q&a python code channel Posting, ensure to offer

Algorithm about

Input a, b, c,
Increasing sequence sorting, get l [3]

If l [0] + [1] l & gt; L [2], in order to do the following judgment
The triangle mark='general triangle'
If l [0] [0] + [1] l * l * l [1] [2]=l * l [2], print 'right triangle, the triangle mark='
If l [0]=l [1] [2]=l, print 'an equilateral triangle, triangle mark='
If l [0]=l [1] OR [2] OR [0]=l l l [1] [2]=l, print 'isosceles triangle, triangle mark='
Print the triangle mark
Otherwise print 'is not a triangle

I want algorithms, the steps and I know that

CodePudding user response:

 s=filling [3] 
S.s ort () 
Print (s) 
A=s [0] 
B=s [1] 
C=s [2] 
If a + b> C: 
Print (' composition triangle ') 
If a b * * * * 2 + 2==c * * 2: 
Print (' right triangle) 
If a==b: 
Print (' isosceles triangle ') 
If b==c: 
Print (' an equilateral triangle ') 

The else: 
Print (' the triangle ')

CodePudding user response:

So!!!!

 
List_1=input (' input, respectively, the length of three sides separated with ", "(middle) : '). The split (', ') 
List_2=[int (I) for I list_1] in 
A, b, c=list_2 [0], list_2 [1], list_2 [2] 
If a + b> C and a - bPrint (' can form a triangle! ') 
If a b * * * * 2 + 2==c * * 2/c * * 2 + 2==b * * * * a 2 b or c * * 2 + 2==a * * * * 2: 
Print (' the triangle is a right triangle! ') 
Elif and b=a==b=c: 
Print (' the triangle is an equilateral triangle! ') 
Elif a==b or a or b===c=c: 
Print (' the triangle is isosceles triangle! ') 
The else: 
Print (' the triangle is a regular triangle! ') 
The else: 
Print (' not form a triangle! ')

Results:

CodePudding user response:

refer to fifth floor try _except response:

this!!!!

 
List_1=input (' input, respectively, the length of three sides separated with ", "(middle) : '). The split (', ') 
List_2=[int (I) for I list_1] in 
A, b, c=list_2 [0], list_2 [1], list_2 [2] 
If a + b> C and a - bPrint (' can form a triangle! ') 
If a b * * * * 2 + 2==c * * 2/c * * 2 + 2==b * * * * a 2 b or c * * 2 + 2==a * * * * 2: 
Print (' the triangle is a right triangle! ') 
Elif and b=a==b=c: 
Print (' the triangle is an equilateral triangle! ') 
Elif a==b or a or b===c=c: 
Print (' the triangle is isosceles triangle! ') 
The else: 
Print (' the triangle is a regular triangle! ') 
The else: 
Print (' not form a triangle! ')

Results:

The sharp-eyed, your meaning is correct!!!!!!
Thank you very much