I want to debug both workout.js and test.js but vscode is debugging only the workout.js how do I set the file name dynamic. so I can debug any js file with one launch.json config
Like "program": "${workspaceFolder}/${currentFileName}.js",
CodePudding user response:
Take a look at the official documentation about variable substitution in Debugging and Task configuration files, there are a few that can be used to achieve what you want.
CodePudding user response:
The easy way is to add multiple settings inside your single lunch config file. and whenever you want to debug any then choose that name while debugging
CodePudding user response:
Reffer this for more details Documnetaion
{
"version": "0.2.0",
"configurations": [
{
"name": "Node js",
"program": "${file}",
"request": "launch",
"skipFiles": ["<node_internals>/**"],
"type": "node"
}
]
}