This piece of code takes in a 7 digit number by a user and returns the same number backwards. However when I enter in a string e.g. "qwerty" it returns me a 1. How do I prevent this from happening and to ensure it works only if user enters a valid 7 digit int?

I have tried using if statements to check the input however it still returns a 1 when I enter a string.

#include <stdio.h>

int main() {
    int num;
    int arr[7];
    printf("Enter a 1-7 digit number: ");
    scanf("}", &num);

    while(num){
        for(int i = 6; i >= 0; i--){
            arr[i] = num;
            num /= 10;
            if(arr[i]){
                printf("%d", arr[i]);
            }
        }
    }

    return 0;
}

CodePudding user response：

You can check the result of scanf function in order to achieve that, see example below.

    [...]
    printf("Enter a 1-7 digit number: ");

    int converted = scanf("}", &num);
    if (converted != 1)
    {
        puts("Input error!");
        return -1;
    }
    [...]

For further information, see scanf man page,

On success, these functions return the number of input items successfully matched and assigned; this can be fewer than provided for, or even zero, in the event of an early matching failure.