creating a new column from Merged columns matching a condition in a dataframe-CodePudding

tweet_id	image_url	doggo	floofer	puppa	puppo
First	row	none	none	none	none
Second	row	doggo	none	none	none
third	row	none	floofer	none	none
fourth	row	none	none	puppa	none
fifth	row	none	none	none	puppo

I have a situation trying to melt the above df columns [doggo,floofer,puppa,puppo] headers which ought to be values. I want to be able to retain the rows count and also have a new_column as table below.

tweet_id	image_url	breed
First	row	none
Second	row	doggo
third	row	floofer
fourth	row	puppa
fifth	row	puppo

I already tried the pd.melt() but it doesn't return desired result. Thank you

CodePudding user response：

I assume your none is string.

df = df.replace('none', np.nan)
df = df.set_index(['tweet_id','image_url'])

output = df.apply(pd.Series.first_valid_index, axis=1).reset_index()
output.columns = ['tweet_id','image_url', 'breed']
output
###
  tweet_id image_url    breed
0    First       row     None
1   Second       row    doggo
2    third       row  floofer
3   fourth       row    puppa
4    fifth       row    puppo

CodePudding user response：

If you are not familiar with pandas function, you can use a nested loop to get the same result too.

df = df.replace('none', np.nan)
df = df.set_index(['tweet_id','image_url'])

result = []
for row in df.to_numpy():
    if pd.isna(row).all():
        result.append(np.nan)
    for breed in row:
        if pd.notna(breed):
            result.append(breed)
            break
            
[nan, 'doggo', 'floofer', 'puppa', 'puppo']

df['breed'] = result

df.reset_index(inplace=True)

  tweet_id image_url  doggo  floofer  puppa  puppo    breed
0    First       row    NaN      NaN    NaN    NaN      NaN
1   Second       row  doggo      NaN    NaN    NaN    doggo
2    third       row    NaN  floofer    NaN    NaN  floofer
3   fourth       row    NaN      NaN  puppa    NaN    puppa
4    fifth       row    NaN      NaN    NaN  puppo    puppo