Excuse me when I was in Python processing car age segmentation,
Use the
Df3 [" old section "]=df3 [" old "]
Df3 [r]. "old section" replace ({0:1 year under the "", 1:1 to 2 years, 2:2-3 years, 3:" 3-4 years ", 4: "four to five years," 5: "five to six years," 6: "six to seven years," 7:7-8 years, 8:8 to 9 years, 9: "9 to 10 years,"??? ,}, inplace=True)
What in? Department said the rest of the data is no replacement for "more than 10 years," thank you!

CodePudding user response:

Can try to write a function and then use the apply

 def age_flag (df) : 
Age_flag_dict={0:1 year under the "", 1:1 to 2 years, 2:2-3 years, 3:" 3-4 years ", 4: "four to five years," 5: "five to six years," 6: "six to seven years," 7:7-8 years, 8:8 to 9 years, 9: "9-10"} 
Age=df (" old ") 
If the age in age_flag_dict: 
Return age_flag_dict [age] 
Esel: 
Return 'more than 10 years' 

Df3 [" old section "]=df3. Apply (age_flag, axis=1) 

CodePudding user response:

Thank you